-p^2-p+5=0

Solution for -p^2-p+5=0 equation:

-p^2-p+5=0

We add all the numbers together, and all the variables

-1p^2-1p+5=0

a = -1; b = -1; c = +5;
Δ = b2-4ac
Δ = -12-4·(-1)·5
Δ = 21
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{21}}{2*-1}=\frac{1-\sqrt{21}}{-2}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{21}}{2*-1}=\frac{1+\sqrt{21}}{-2}
$